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The sum of first three terms of an AP is 48. If the product of first and second terms exceeds 4 times the third terms by 12. Find the AP.

Posted by Pankaj Uraon 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 10 months ago

Let the first three terms of the AP be (a-d), a and (a+d). Then,
(a -d) + a + (a + d) = 48
⇒ 3a = 38
⇒ a = 16
Now,
(a - d) × a = 4(a + d) + 12 (Given)
⇒ (16 -d) × 16 = 4(16 + d) + 12
⇒16d + 4d = 256 - 76
⇒20d = 180
⇒ d= 9
When a= 16, d= 9
⇒ a - d = 16 - 9 = 5
a + d = 16 + 9 = 25
Hence, the first three terms of the AP are 7, 16, and 25.

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