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√3cosx+sinx=√2 solve

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√3cosx+sinx=√2 solve
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Sherry Bansal 6 years, 10 months ago

√3/2(cosx) +1/2(sinx)=1/√2 => cosπ/6•cosx + sinπ/4•sinx =1/√2 => cos(x-π/6)=cosπ/4 => x-π/6= 2nπ+_π/4 => x= 2nπ+π/6+-π/4
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