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Prove that (secA+tanA-1)(secA-tanA+1)=2/cotA

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Prove that (secA+tanA-1)(secA-tanA+1)=2/cotA
  • 2 answers
Atleast answer to mila mujhe

Puja Sahoo? 6 years, 10 months ago

Yup, se...here ..---> (secA+tanA-1)(secA-tanA+1) -----> (secA +tanA-1){secA-(tanA-1)}..................... ----->sec square A - ( tanA - 1)square ................... ------> sec square A-(tan square A+1-2tanA) ........ ----> sec square A-tan square A - 1+ 2 tanA......... ----> 1-1+2tanA........ ----> 2tanA..... ------> 2/ cotA.. HENCE PROVED......☺☺
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