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(sinA÷secA+tanA-1)+(cosA÷cosecA+cotA-1)

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(sinA÷secA+tanA-1)+(cosA÷cosecA+cotA-1)
  • 1 answers

Surendrapal Singh Singh Gaur 6 years, 10 months ago

Take the first term ...and split it => SinA/secA + sinA/tanA - sinA => SinAcosA + cosA - sinA In the same way split the second term...it will result in cosAsinA + sinA - cosA Add both...=> After elimination there will be left only ( sinAcosA )^2 Change cos A as 1/sinA SinA will be cancelled out and ( 1 ) ^2= 1 Hence proved!!
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