No products in the cart.

Proton move with a speed of …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Proton move with a speed of 7.45 x 10 ^5 m /s directly towards a free Proton initially at rest find the distance of the closest approach for the two protons
  • 1 answers

Sangitaben Patel 6 years, 10 months ago

Apply energy conservation... KE=PE 1/2 x mass of proton x velocity^2. =. (ke^2)/r Where r = distance of closest approach
https://examin8.com Test

Related Questions

Derivation of ohm's law class 12
  • 0 answers
what us current
  • 2 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App