If cos x=_3/5,x liesin the third …
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Posted by Sanm Khan 6 years, 10 months ago
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Ram Kushwah 6 years, 10 months ago
{tex}\begin{array}{l}\cos x=\frac35\\\sin x=\sqrt{1-\frac9{25}}=\sqrt{\frac{16}9}=\pm\frac45\\\end{array}{/tex}
In 3rd quadrant
sin is -ve so sinx = -4/5
tan is -ve so tanx= -(4/5)/3/5= -4/3
other ratios can be calculated
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