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Find the HCF of 92690, 7378,7161 …

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Find the HCF of 92690, 7378,7161 use its Euclid division algorithm

Posted by Jaiharish Harish 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

We have to find the HCF, by Euclid's division algorithm of the numbers 92690, 7378 and 7161.
Here, we will apply Euclid's Division Lemma, we have
92690 = 7378 × {tex}{/tex}12 + 4154
Again we apply Euclid's Division Lemma of divisor 7,378 and remainder 4154, thus we have
7378 = 4154 × {tex}{/tex}1 + 3,224
4154 = 3224 × {tex}{/tex}1 + 930
3224 = 930 × 3 {tex}{/tex} + 434
930 = 434 × 2 {tex}{/tex}+ 62
434 = 62 × {tex}{/tex}7 + 0
HCF of 92690 and 7378= 62
Now, using Euclid's Division Lemma on 7161 and 62, we have
7161 = 62 × {tex}{/tex}115 + 31
Again, applying Euclid's Division Lemma on divisor 62 and remainder 31, we have
62 = 31 × {tex}{/tex}2 + 0
Clearly, HCF of 7161 and 62 = 31
Hence, HCF of 92690, 7378 and 7161 is 31.

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