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If A,B and C are interior angle of triangle than prove that Sin (B+C/2) =Cot (A/2)

Posted by Sahil Patel 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Naitik Tayal 6 years, 11 months ago

A B C are interiors angle then A+B+C= 180 PUT the value of B+C in sin( B+C÷ 2) Sin( 180-A/2)=sin(90-A/2)=cos(A/2) Your question is wrong it is not cot it is cos

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CBSE > Class 10 > Mathematics