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If tan(A+B)=√3 and tan (A+B)= 1\√3;0°B …

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If tan(A+B)=√3 and tan (A+B)= 1\√3;0°<A+<=90°;A>B Find A and B

Posted by Sujan Nepal 6 years, 11 months ago

Adhya Singh 6 years, 11 months ago

Tan(A+B)=√3. Tan(A-B)=1/√3 Tan(A+B)=Tan60°. Tan(A-B)=tan30° A+B=60°. A-B=30° A+B=60° A-B=30° 2A=90° A=45° A+B=60° 45°+B=60° B=60°-45° B=15°

Janhvi Singh 6 years, 11 months ago

tan(A+B)=tan 60' so A+B=60 similarly Tan(A+B) =tan30' so A + B =30 now solve these equations you will get answers

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