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Complete square method

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Complete square method

    • Posted by Rohini Sv0 6 years, 11 months ago

    CBSE > Class 10 > Mathematics
    • 4 answers

    Anshika & Aliens???? 6 years, 11 months ago

    Example : Solve 5x2 – 4x – 2 = 0 Step 1 Divide all terms by 5 x2 – 0.8x – 0.4 = 0 Step 2 Move the number term to the right side of the equation: x2 – 0.8x = 0.4 Step 3 Complete the square on the left side of the equation and balance this by adding the same number to the right side of the equation: (b/2)2 = (0.8/2)2 = 0.42 = 0.16 x2 – 0.8x + 0.16 = 0.4 + 0.16 (x – 0.4)2 = 0.56 Step 4 Take the square root on both sides of the equation: x – 0.4 = ±√0.56 = ±0.748 (to 3 decimals) Step 5 Subtract (-0.4) from both sides (in other words, add 0.4): x = ±0.748 + 0.4 = -0.348 or 1.148

    2Thank You

    Anshika & Aliens???? 6 years, 11 months ago

    If it is easy so do it instead of saying no ok jatin . rohini i will give u example wait ?

    1Thank You

    Anshika & Aliens???? 6 years, 11 months ago

    To solve ax2+bx+c=0 by completing the square: 1. Transform the equation so that the constant term, c , is alone on the right side. 2. If a , the leading coefficient (the coefficient of the x2 term), is not equal to 1 , divide both sides by a . 3. Add the square of half the coefficient of the x -term, (b2a)2 to both sides of the equation. 4. Factor the left side as the square of a binomial. 5. Take the square root of both sides. (Remember: (x+q)2=r is equivalent to x+q=±r√ .) 6. Solve for x .

    1Thank You

    Jatin Singh 5 years, 8 months ago

    It is a very siple question so i will not do it

    2Thank You

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