A bucket in the form of …
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Yogita Ingle 6 years, 11 months ago
R = 14 cm
r = 10.5 cm
Let height of frustum be h cm
∴ Volume held by bucket = 14245 cm³
Also,
Volume of frustum = π(R²+Rr+r²)h/3
⇒ 14245 = 22× (196+ 147+110.25 )× h/(3× 7)
⇒ 453.25 h = 14245*21/22
⇒ 453.25 h = 13597. 5
⇒ h = 13597.5/453.25 = 30cm
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