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If k-1, k+3 and 3k-1are in …

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If k-1, k+3 and 3k-1are in AP ;then find the value of k
  • 5 answers

Sanket Saroj 6 years, 10 months ago

a3 -a2 = a2 -a1 3k-1 -(k+3) = k+3 -(K-1) 3k-1 - k - 3 = k+3-k+1 2k -4 = 4 2k = 4+4 2k = 8 K = 8/2 K = 4

Shivam Tripathi 6 years, 10 months ago

Send solution

Kajal Singh 6 years, 10 months ago

If it is in ap then d=(k+3)-(k-1) => k+3-k+1 => 4 (3k-1)-(k+3) should be 4 => 3k-1-k-3=4 => 2k-4=4 => 2k=8 => k = 4

Honey ??? 6 years, 10 months ago

Subtract 2nd term from 3rd term and also 1st term from 2nd term both will be equal as they arr commn diff. of an A.P.

Honey ??? 6 years, 10 months ago

4
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