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If a sum of a no. …

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If a sum of a no. And it's resiprocal is 26 /5 . Find number.

    • Posted by Divya Chavada 6 years, 11 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Umaid Shafi 6 years, 11 months ago

    Let the no be x So its reciprocal is 1/x According to question x+1/x=26/5 5(Xsq+1)=26x 5Xsq-5-26x=0 5Xsq-26x+5=0 5Xsq-26x+x+5=0 5x(x-5)-1(x-5)=0 x=1/5 & x=5

    2Thank You

    Sumedh Dabir 6 years, 11 months ago

    x + 1/x = 26/5 represents the given statement. Solve for x. since x cannot be zero (which has no reciprocal), you can multiply all terms by x to get x2 +1 = (26/5) x. You have to solve for x. It's a quadratic equation: multiply by 5 to get: 5x2 -26x +5 = 0.

    0Thank You

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    CBSE > Class 10 > Mathematics
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