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Solve for x and y: 2x+3y=7 …

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Solve for x and y: 2x+3y=7 (a+b+1)x+(a+2b+2)y=4 (a+b)+1

Posted by Saransh Jaiswal 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

If infinite number of solutions,
{tex}\frac{{{a_1}}}{{{a_2}}} = \frac{{{b_1}}}{{{b_2}}} = \frac{{{c_1}}}{{{c_2}}}{/tex}
or {tex}\frac{2}{{a + b + 1}} = \frac{3}{{a + 2b + 2}} = \frac{7}{{4a + 4b + 1}}{/tex}
If {tex}\frac{2}{{a + b + 1}} = \frac{3}{{a + 2b + 2}}{/tex}
{tex}\Rightarrow{/tex} a - b = 1
and if {tex}\frac{3}{{a + 2b + 2}} = \frac{7}{{4a + 4b + 1}}{/tex}
{tex}\Rightarrow{/tex} 5a - 2b = 11
On solving we get,
a = 3 and b = 2

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