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Sum of the areas of two …

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Sum of the areas of two squares is 468m^2. If the difference of their perimeter is 24m. Find the sides of the two squares. PLZ SOLVE IT

Posted by Jot Virk?♠ 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Sarthak Paliwal 6 years, 11 months ago

Let side of first square be x Side of another square be y Perimeter of one square - perimeter of another =24 4x-4y=24 X-y=6 Y=x-6 Now. ar of first square + area of another =468 X^2 +y^2=468 Here, y can be written as x-6 X^2 +(x-6)^2=468 ??After solving it you will get answer

2Thank You

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