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??CHALLENGE?? U CAN IMAGINE ANSWER BUT …

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??CHALLENGE?? U CAN IMAGINE ANSWER BUT CAN'T SOLVE THIS QUESTIONIN A PROPER WRITING WAY //// In a class there are 48 students and regular students are more than irregular than .If 2 irregular students be regular the product of the two types of student be 380 find the number of each type of students .

Posted by Fully Danger 6 years, 11 months ago

CBSE > Class 10 > Mathematics

5 answers

Puja Sahoo? 6 years, 11 months ago

Bhai, bt eq to x square + 44x - 268=0 ani chahiye

Fully Danger 6 years, 11 months ago

Niche galat hai equation Ye hai 44x-x square -284=0

Fully Danger 6 years, 11 months ago

=0

Fully Danger 6 years, 11 months ago

Ye equation aa rhai hai 44x-x square+92-2x

Puja Sahoo? 6 years, 11 months ago

Let, no. of regular students be x and irregular will be 48-x. Now, if 2 irregular students became regular, so regular students------> x+2 and irregular students--------> 48-x-2. --> 46-x. Now, A.T.Q.......(x+2)(46-x)=380.........solve this the answer will be regular students 36, and irregular students 12.........as the value of x yu will get 36.

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