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Yogita Ingle 6 years, 10 months ago
{tex}\begin{array}{l}\frac x8-\;\frac12=\;\frac x{6-2}\\\frac x8-\;\frac12=\;\frac x4\\\frac x8-\frac x4=\;\frac12\\\frac{x\;-\;2x}8\;=\;\frac12\end{array}{/tex}
- x = 4
x = -4
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