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AD is an altitude of a …

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AD is an altitude of a equilateral triangleABC on AD as a base another equilateral triangleADE is constructed Ar(ADE):Ar(ABC)

    • Posted by Sri Kumar 6 years, 11 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Gaurav Seth 6 years, 11 months ago

    Guess the question is incomplete.

    The solution is as per this question:

    Question:AD is an altitude of an equilateral triangle ABC. On AD as a base,another equilateral triangle ADE is constructed.Prove that area(ADE):area(ABC)=3:4.

    <hr />

    We have,
    ΔABC is an equilateral triangle
    Then, AB = BC = AC
    Let, AB = BC = AC = 2x
    Since, AD ⊥ BC then BD = DC = x
    In ΔADB, by Pythagoras theorem

    By area of similar triangle theorem

    2Thank You

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