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For what value of p are …

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For what value of p are 2p+1,13,5p-3 three consecutive terms of an ap
  • 1 answers

Mohit Sharma 7 years, 10 months ago

Given 2p+1, 13 , 5p-3 are in AP.

To find: value of P

If a,b,c are in AP then we know that 
2b=( a+c)
Here a= 2p+1
b=13
c=5p-3

2 (13) =(2p+1+5p-3)

26=7p-2

26+2=7p

28=7p

p=28/7 =4

Therefore the value of
P is 4.

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