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in figure DE parallel to BC then find value of x given AD=2cm DB=3cm DE=4cm and BC=x

Posted by Supriya Sahoo 7 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 7 years, 2 months ago

Given That AD=2 cm , DB=3 cm DE= 4 cm BC=x

{tex}\begin{array}{l}As\;DE\parallel\;BC\\So\\\frac{AD}{AB}=\frac{DE}{BC}\\\frac2{2+3}=\frac4x\\2x=4\times5=20\\x=10\\\end{array}{/tex}

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CBSE > Class 10 > Mathematics