in figure DE parallel to BC …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Supriya Sahoo 6 years, 11 months ago
- 1 answers
Related Questions
Posted by Hari Anand 6 months, 2 weeks ago
- 0 answers
Posted by Kanika . 1 month, 1 week ago
- 1 answers
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
Posted by Parinith Gowda Ms 3 months, 3 weeks ago
- 1 answers
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers
Posted by Parinith Gowda Ms 3 months, 3 weeks ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Ram Kushwah 6 years, 11 months ago
Given That AD=2 cm , DB=3 cm DE= 4 cm BC=x
{tex}\begin{array}{l}As\;DE\parallel\;BC\\So\\\frac{AD}{AB}=\frac{DE}{BC}\\\frac2{2+3}=\frac4x\\2x=4\times5=20\\x=10\\\end{array}{/tex}
2Thank You