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The sum of four consecutive number in an AP is 32 and the ratio of the product of the first and the last term to the product of two middle terms is 7:15. Find the number

Posted by Ankul Prajapati 7 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Veeraraghavan Pandurangan 7 years, 2 months ago

Let the four consecutive numbers in AP in be a-3d,a-d,a+d,a+3d According to question a-3d+a-d+a+d+a-3d=32 4a=32 a=8 (a-3d)(a+3d)/(a-d)(a+d)=7/15 (a^2-9d^2)(a^2-d^2)=7/15 8a^2=128d^ a^2=16d^2 a=4d 8=4d d=2,a=8, Nos are a-3d,a-d,a+d,a+3d, 2,6,10,14 are the numbers

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