A person invested some amount at …
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Posted by Love Sharma 6 years, 10 months ago
- 2 answers
Ram Kushwah 6 years, 10 months ago
{tex}\begin{array}{l}let\;the\;amount\;are\;m\;and\;n\\interest\;I_1=\frac{mx12x1}{100}=\frac{12m}{100}\\I_2=\frac{nx10x1}{100}=\frac{10n}{100}\\I_1+I_2=\frac{12m+10n}{100}=130\\or\;12m+10n=13000\;......(1)\\If\;he\;reverse\;the\;investment\;then\\10m+12n=13400.......(2)\\\\\end{array}{/tex}
{tex}\begin{array}{l}on\;multiplying\;(1)\;by\;5\;and\;(2)\;by\;6\\60m+50n=65000---(3)\\60m+72n=80400----(4)\\subtract\;(3)\;from\;(4)\\22n=15400\\n=\frac{15400}{22}=700\;Rs\\putting\;value\;of\;n\;in\;(1)\\12m+10x700=13000\\12m=13000-7000=6000\\m=500\;Rs\\ans\;is\;Rs\;700\;and\;500\end{array}{/tex}
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Dharmendra Kushwaha 6 years, 10 months ago
0Thank You