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Find the real no. whose product with irrational number, 4-√3 is 39

Posted by Chirag Sankhyan 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 11 months ago

{tex}\begin{array}{l}Let\;the\;number\;is\;x\\so\;x(4-\sqrt3)=39\\x=\frac{39}{(4-\sqrt3)}=\frac{39(4+\sqrt3)}{(4-\sqrt3)(4+\sqrt{3)}}=\frac{39(4+\sqrt3)}{16-3}\\=\frac{39(4+\sqrt3)}{13}=3(4+\sqrt3)\\\end{array}{/tex}

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CBSE > Class 10 > Mathematics