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if x = sin A cos …

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if x = sin A cos B , y = r sin A sin B and z = r cos A , show that x^2 + y^2 + z^2 = r^2 .
  • 1 answers

Sia ? 6 years, 6 months ago

We have,
x+ y2 + z2 = r2sin2{tex}\alpha{/tex}cos2{tex}\beta{/tex} + r2sin2{tex}\alpha{/tex} sin2{tex}\beta{/tex} + r2cos2{tex}\alpha{/tex}
= r2sin2{tex}\alpha{/tex} (cos2{tex}\beta{/tex} + sin2{tex}\beta{/tex}) + r2cos2{tex}\alpha{/tex}
= r2sin2{tex}\alpha{/tex} + r2cos2{tex}\alpha{/tex} [{tex}\because{/tex} cos2{tex}\beta{/tex} + sin2{tex}\beta{/tex} = 1]
= r2(sin2{tex}\alpha{/tex} + cos2{tex}\alpha{/tex}) = r2 [{tex}\because{/tex} sin2{tex}\alpha{/tex} + cos2{tex}\alpha{/tex} = 1].
Hence, (x2 + y2 + z2) = r2.

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