Solve for x(in term of a. …

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Sia ? 6 years, 6 months ago
The given equation can be rewritten as
{tex}\frac { a ( x - a ) + b ( x - b ) } { ( x - b ) ( x - a ) } = 2{/tex}
a(x -a) + b(x- b) = 2[x2 - (a + b)x + ab]
ax- a2 + bx - b2 = 2x2- 2(a + b)x + 2ab
2x2- 3(a + b)x + (a + b)2 = 0
2x2 - 2(a + b) x - (a + b)x + (a + b)2 = 0
{tex}2x[x-(a+b)]-(a+b)[x-(a+b)]{/tex}
[2x - (a + b)] [x - (a + b)] = 0
{tex}x = a + b , \frac { a + b } { 2 }{/tex}
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