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Divide 24 in 3 parts such …

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Divide 24 in 3 parts such that they are in AP and their product is 440 ??

Posted by Anshika & Aliens???? 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Lavina Rajput ??? 6 years, 11 months ago

Solution:- Let the required terms of the given AP be a-d, a and a+d * Where the first term is a-d* The common difference = d* Given : The sum of the three parts = 24* ∴ (a-d)+(a)+(a+d) = 24 3a = 24 # a = 8# Given : The product of these three terms = 440 ∴ (a-d) (a) (a+d) = 440# (8-d) (8) (8+d) = 440# - 8d² + 512 = 440# - 8d² = 440 - 512# - 8d² = - 72# d² = 72/8# d² = 9# d = √9# d= 3# So the three required terms of AP is 8 - 3 = 5 ; 8 and 8 + 3 = 11 Three terms are 5, 8, 11

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