The centre of a circle is(2a-1,7) …
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Ram Kushwah 6 years, 7 months ago
Let O(2a-1,7) is the center and A(-3,-1) is on the circumference then
OA=r=20/2=10
{tex}\begin{array}{l}OA^2=10^2=100\\or\;\;(2a-1+3)^2+(7+1)^2=100\\\;\;(2a+2)^2+64=100\\4a^2+8a+4+64=10\\4a^2+8a-32=0\\a^2+2a-8=0\\(a+4)(a-2)=0\\Hene\;a=-4\;and\;2\end{array}{/tex}
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