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If x=3 is one root of …

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If x=3 is one root of the quadratic eq x2-2kx-6=0
  • 7 answers

Augustya Singh 6 years, 11 months ago

x2-2kx-6=0 (3)square-6k-6 9-6k-6=0 3-6k=0 -6k=-3 k=-3/-6 k =1/2

Murari Barnwal 6 years, 11 months ago

(x)2 -2kx -6=0 ,(3)2-2k(3)-6=0 9-6k-6=0 3-6k=0 So, k=1/2

Yogita Ingle 6 years, 11 months ago

k = 1/2

Yogita Ingle 6 years, 11 months ago

sorry wrong solution added.
Correct solution is
x2 - 2kx - 6 = 0
x = 3
(3)2 - 2k(3) - 6 = 0
9 - 6k - 6 = 0
- 6k + 3 = 0
6k = 3
k = 3/6
k = 1/3

Yogita Ingle 6 years, 11 months ago

x2 - 2kx - 6 = 0
x = 3
(3)2 - 2k(3) - 6 = 0
9 - 6k - 6 = 0
2 - 6k = 0
6k = 2
k = 2/6
k = 1/3

Jiya Arora????? 6 years, 11 months ago

Let p(x)=x^2-2kx-6 Let X = 3 in p(x) p(3)=(3)^2 - 2k(3) -6 =9-6k-6 =3-6k -3=-6k 3=6k 3/6=k 1/2=k

X Y 6 years, 11 months ago

Value of k=6
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