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1-sin A ÷1+sinA = (secA+tanA)²

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1-sin A ÷1+sinA = (secA+tanA)²

Posted by Spark Light 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

Shreyanka Das 6 years, 11 months ago

Very nice explain gaurav seth

0Thank You

Gaurav Seth 6 years, 11 months ago

1-sinA/1+sinA=(secA-tanA)²

L.H.S

1-sinA/1+sinA

Rationalising the denominator

1-sinA (1-SinA) /1+sinA(1-SinA)

(1-SinA)²/ 1² -(Sin²A)

(1-SinA)²/ 1 -(Sin²A)

(1-SinA)² /Cos² A

[ 1 -Sin²A = cos²A]

(1-SinA/CosA)²

(1/CosA-SinA/CosA)²

(SecA-tanA)²

L.H S = R H.S

4Thank You

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Posted by Kanika . 1 month, 1 week ago

CBSE > Class 10 > Mathematics