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Plz help If 7 times of 7th term of an A.P is equal to 11 times of 11th term of an A.P. then find the value of 18th term

Posted by Bahubali Gaming 6 years, 11 months ago

CBSE > Class 10 > Mathematics

3 answers

Anshika & Aliens???? 6 years, 11 months ago

7th term = (a+6d) 11th term = (a+10d) (a+6d)7 since 7th term of the ap is 7 times and the same for 11th term (a+6d)7=(A+10d)11 (given) 7a + 42d =11a +110d (on solving) 7a - 11a = 110d - 42d -4a = -68d a= -17d we know 18th term = (a+17d)................................. (i) now we substitute the value of a in (i) which emplies, -17d + 17d = 0 hence prove..

Sumit Rajput 6 years, 11 months ago

What is a sun light

Avinash Saigal 6 years, 11 months ago

7th term = (a+6d) 11th term = (a+10d) (a+6d)7 since 7th term of the ap is 7 times and the same for 11th term (a+6d)7=(A+10d)11 (given) 7a + 42d =11a +110d (on solving) 7a - 11a = 110d - 42d -4a = -68d a= -17d we know 18th term = (a+17d)................................. (i) now we substitute the value of a in (i) which emplies, -17d + 17d = 0 Thank you??

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