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Cos 45 /sec 30 + cosec …

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Cos 45 /sec 30 + cosec 30 please explain me how to do this????

    • Posted by Anshika & Aliens???? 6 years, 11 months ago

    CBSE > Class 10 > Mathematics
    • 4 answers

    Ram Kushwah 6 years, 11 months ago

    {tex}\begin{array}{l}\frac{\cos45}{sec30}+\cos ec30\\=\frac{\displaystyle\frac1{\sqrt2}}{\displaystyle\frac2{\sqrt3}}+2=\frac1{\sqrt2}\times\frac{\sqrt3}2+2\\=\frac{\sqrt3}{2\sqrt2}+2\\=\frac{\sqrt3{\displaystyle+}{\displaystyle4}{\displaystyle\sqrt2}}{2\sqrt2}=\frac{1.73+4\times1.41}{2\times1.41}=\frac{1.73+5.64}{2.82}\\=\frac{7.37}{2.82}=2.613\\\end{array}{/tex}

    0Thank You

    Anshika & Aliens???? 6 years, 11 months ago

    I had puteen thia value but i m not able to solve please explain it

    1Thank You

    Puja Sahoo?‍♀️ 6 years, 11 months ago

    Hope it will help you

    3Thank You

    Puja Sahoo?‍♀️ 6 years, 11 months ago

    Just put the values and then solve, cos 45= 1/root2 , sec 30= 2/root3, and cosec 30=2.

    3Thank You

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