Cos(3π/4+x)-cos(3π/4-x)=-√2sinx
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Wasim Ansari 9 years, 1 month ago
- 1 answers
Test
Related Questions
Posted by Ananya Sv 1 year, 5 months ago
- 1 answers
Posted by Sethpoulou Apoulou 1 year, 5 months ago
- 0 answers
Posted by Nitin Kumar 1 year, 4 months ago
- 1 answers
Posted by Sana Dharwad 1 year, 4 months ago
- 0 answers
Posted by Manoj Thakur 1 year, 4 months ago
- 0 answers
Posted by Ashish Chaudhary 1 year, 4 months ago
- 1 answers
Posted by Gurleen Kaur 1 year, 4 months ago
- 0 answers
Posted by Sabin Sultana 1 year, 4 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Rashmi Bajpayee 9 years, 1 month ago
L.H.S. = Cos(3π/4+x)-cos(3π/4-x)
= cos 3π/4 cos x - sin 3π/4 sin x - [cos 3π/4 cos x + sin 3π/4 sin x]
= cos 3π/4 cos x - sin 3π/4 sin x - cos 3π/4 cos x - sin 3π/4 sin x]
= -2sin 3π/4 sin x
= -2 x (1/√2) sin x
= -√2sin x
0Thank You