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Evaluate..cot12°cot38°cot52°cot60°cot78°

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Evaluate..cot12°cot38°cot52°cot60°cot78°

Posted by Kabita Beura 6 years, 11 months ago

CBSE > Class 10 > Mathematics

4 answers

Himanshi Sharma 6 years, 11 months ago

1/root3

Ram Kushwah 6 years, 11 months ago

cot12cot38cot52cot60cot78

=cot(90-78)cot(90-52)cot52cot60cot78

=tan78cot78 x tan52cot52 x cot60

=1x1x1 x cot60

={tex}\frac{1}{\sqrt3}{/tex}

Vaishnavi Singh 6 years, 11 months ago

1/√3

Vishal Gorana 6 years, 11 months ago

1/√3

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Posted by Kanika . 1 month, 1 week ago

CBSE > Class 10 > Mathematics

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This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.

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Posted by Hari Anand 6 months, 2 weeks ago

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