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4-3√2/4+3√2 Rationalize following

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4-3√2/4+3√2

Rationalize following

Posted by Parvendra Chouhan 8 years, 8 months ago

CBSE > Class 09 > Mathematics

1 answers

Payal Singh 8 years, 8 months ago

Solution : {tex}{4-3\sqrt 2\over 4+3\sqrt 2}{/tex}

Rationalise it denominator,

{tex}= {4-3\sqrt 2\over 4+3\sqrt 2} \times {4-3\sqrt 2\over 4-3\sqrt 2}{/tex}

{tex}= {(4-3\sqrt 2)^2\over( 4)^2-(3\sqrt 2)^2}{/tex} using (a+b)(a-b) = a²- b²

{tex}= {16-24\sqrt 2 + 18\over 16-18} {/tex}

{tex}= {34-24\sqrt 2\over -2}{/tex}

{tex}= {-17 +12\sqrt 2}{/tex}

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