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Sum of the areas of two …

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Sum of the areas of two squares is 468msquare . If the difference of their perimeter is 24m , find the sides of the 2 squares??

Posted by Anshika Pal???? 6 years, 11 months ago

CBSE > Class 10 > Mathematics

3 answers

Neha Sirur 6 years, 11 months ago

Perimeter =4x Diffrence is 24 4x=24+4x X=x+6 which is the length of each side Sum of areas is 468m2 X^2+ (6+x)^2= 468 X^2+6x-216=0 Solve it ans is 18 and 12

1Thank You

Puja Sahoo? 6 years, 11 months ago

18m, and 12m.its ncert question yu can check in this app.

1Thank You

Neha Sirur 6 years, 11 months ago

It is ncert text bk question exercise 4.3

0Thank You

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CBSE > Class 10 > Mathematics