The radius and height of a …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Kanika . 1 month, 1 week ago
- 1 answers
Posted by Hari Anand 6 months, 1 week ago
- 0 answers
Posted by Parinith Gowda Ms 3 months, 3 weeks ago
- 0 answers
Posted by Parinith Gowda Ms 3 months, 3 weeks ago
- 1 answers
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Sia ? 6 years, 4 months ago
Let the ratio be x
{tex}\therefore{/tex} Radius 'r' = 5x
Height 'h' = 12x
{tex}\therefore{/tex} Slant height = {tex}\sqrt { r ^ { 2 } + h ^ { 2 } } = \sqrt { ( 5 x ) ^ { 2 } + ( 12 x ) ^ { 2 } }{/tex} =13x
Now, volume = 314 m3 [given]
{tex}\Rightarrow {/tex} {tex}\frac { 1 } { 3 } \pi r ^ { 2 } h{/tex} = 314
{tex}\Rightarrow {/tex} {tex}\frac { 1 } { 3 }{/tex} {tex}\times{/tex} 3.14 {tex}\times{/tex} 25 x2 {tex}\times{/tex} 12x = 314
{tex}\Rightarrow {/tex} x3 = {tex}\frac { 314 \times 3 } { 3.14 \times 25 \times 12 }{/tex}
{tex}\Rightarrow {/tex} x = 1
{tex}\therefore{/tex} Slant height = 13x = 13m
Radius = 5x = 5m
0Thank You