The sum of first, third and …

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Posted by Gudia Kumari 6 years, 11 months ago
- 3 answers
Gaurav Seth 6 years, 11 months ago
nth term of an A.P whose starting term is "a" and common difference is "d"
is an = a+(n-1)d
1st term = a 3rd term =a+2d 17th term = a+16d
According to question
a+a+2d+a+16d=216
3a+18d=216
3(a+6d) = 216
a+6d= 216/3
a+6d= 72
Sum of "n" terms in an AP = n(2a+(n-1)d)/2
Sum of thirteen terms = 13(2a+12d)/2
=13(a+6d) = 13*72 = 936
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Nakul Sharma 6 years, 11 months ago
2Thank You