If ∆FEC≅∆GDB, ∠1=∠2. Prove that ∆ADE~∆ABC

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Posted by Veena Katti 6 years, 11 months ago
- 1 answers
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Gaurav Seth 6 years, 11 months ago
Given : ∆ FEC ≅ ∆ GBD ,
SO From CPCT
WE GET,
BD = CE ----------------- ( 1 )
ALSO GIVEN : ∠ 1 = ∠ 2 ,
SO FROM BASE
ANGLE THEOREM IN ∆ ADE
WE GET
AD =AE ------------------------ ( 2 )
From equation 1 and 2 we get
ADBD = AECE , So from converse of B.P.T. we get
DE | | BC
THEN ,
∠ 1 = ∠ 3
( CORRESPONDING ANGLES AS DE | | BC AND AB IS TRANSVERSAL LINE )
AND
∠ 2 = ∠ 4 ( CORRESPONDING ANGLES AS DE | | BC AND AC IS TRANSVERSAL LINE )
FROM ABOVE TWO EQUATIONS WE CAN SAY THAT :
∆ ADE ~ ∆ ABC ( ByAArule )
( Hence proved )
1Thank You