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If ∆FEC≅∆GDB, ∠1=∠2. Prove that ∆ADE~∆ABC

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If ∆FEC≅∆GDB, ∠1=∠2. Prove that ∆ADE~∆ABC
  • 1 answers

Gaurav Seth 6 years, 11 months ago

Given : ∆ FEC ≅ ∆ GBD  , 

SO From CPCT

WE GET,

BD = CE ----------------- ( 1 )

ALSO GIVEN : ∠ 1 =  ∠ 2  ,

SO FROM BASE 

ANGLE THEOREM IN ∆ ADE

WE GET

AD  =AE ------------------------ ( 2 ) 

From equation 1 and 2 we get

ADBD = AECE , So from converse of B.P.T. we get

DE | | BC

THEN ,

∠ 1  = ∠ 3                                  
( CORRESPONDING ANGLES AS DE  | | BC AND AB IS TRANSVERSAL LINE )

AND

∠ 2  = ∠ 4                                  ( CORRESPONDING ANGLES AS DE  | | BC AND AC IS TRANSVERSAL LINE )

FROM ABOVE TWO EQUATIONS WE CAN SAY THAT :

∆ ADE ~ ∆ ABC        ( ByAArule )
( Hence proved )

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