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E is a point on the side AD produced of parallelogram ABCD and BE intersects CD at F show that ABEis similar to CFB

Posted by Manorama Mishra 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Gurjar Kabir (बैंसला) 6 years, 11 months ago

In ΔABE and ΔCFB, ∠A = ∠C (Opposite angles of a parallelogram) ∠AEB = ∠CBF (Alternate interior angles as AE || BC) ∴ ΔABE ~ ΔCFB (By AA similarity criterion)

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