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Sin (1+tan)+ cos(1+cot)=sec+cosec

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Sin (1+tan)+ cos(1+cot)=sec+cosec
  • 1 answers

Gaurav Seth 6 years, 4 months ago

According to given sum,

sin (1+tan)+cos (1+cot)=sec+cosec 

=> LHS= sin (1+tan)+cos (1+1/tan)

=> sin (1+tan)+cos (1+tan)/tan

=> (1+tan)(sin+cos/tan)

=> (1+tan)(sin.tan+cos)/tan

=> (1+tan)(sin2/cos+cos)/tan

=> (1+tan)(sin2+cos2)/tan.cos

=>(1+tan)/tan.cos

=>(1/tan.cos)+tan/tan.cos

=>( cot/cos)+(1/cos)

=> cosec +sec

LHS= RHS.

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