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Find K if the sum of the zeroes of the polynomial x^2-(K+6)x+2(2K-1) is half of their product

Posted by Aa Bisht 6 years, 11 months ago

CBSE > Class 10 > Mathematics

3 answers

Gurjar Kabir (बैंसला) 6 years, 11 months ago

Given quadratic polynomial, x² - (k+6)x + 2(2k+1) = 0 By comparing it with ax²+bx+c = 0,we get a = 1 , b = -(k+6) , c = 2(2k+1) Sum of zeroes = -b/a = -[-(k+6)]/1 = k+6 Product of zeroes = c/a = 2(2k+1)/1 = 2(2k+1) Now..... Sum of zeroes = ½ × product of zeroes k+6 = ½ × 2(2k+1) k+6 = 2k+1 2k-k = 6-1 k = 5 Hope it helps

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Aa Bisht 6 years, 11 months ago

Plz plz.....

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Aa Bisht 6 years, 11 months ago

Answer fast guys it's urgent

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CBSE > Class 10 > Mathematics

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Don't post personal information, mobile numbers and other details.
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Posted by Hari Anand 6 months, 1 week ago

CBSE > Class 10 > Mathematics