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What is the value of m is mx(x+7)49

Posted by Priti Chouhan 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

{tex}mx(x - 7) +49 = 0{/tex} {tex}\Rightarrow{/tex} {tex}mx^2 - 7mx + 49 = 0{/tex}
Here a = m, b = -7m, c = 49
{tex}\Rightarrow{/tex} {tex}D = b^2 - 4ac{/tex}
For equal roots, D = 0
{tex}\Rightarrow{/tex} 0 = (-7m)² - 4 {tex}\times{/tex} m {tex}\times{/tex} 49
{tex}\Rightarrow{/tex} {tex}0 = 49m^2 - 196m{/tex}
{tex}\Rightarrow{/tex} {tex}49m^2 - 196m = 0{/tex}
{tex}\Rightarrow{/tex} {tex}7m(7m - 28) = 0{/tex}
{tex}\Rightarrow{/tex} 7m = 0 or 7m - 28 = 0
{tex}\Rightarrow{/tex} m = 0 or m = {tex}\frac{28}{7}{/tex} = 4
but m {tex}\ne{/tex} 0 [{tex}\because{/tex}In quadratic a {tex}\ne{/tex} 0]
{tex}\therefore{/tex} m = 4

0Thank You

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