A copper rod of diameter 1 …

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Yogita Ingle 6 years, 11 months ago
Given diameter of the copper rod = 1 cm
So, radius(r) of the copper rod = 1/2 cm
Let R is the radius of the cross section(circular) of the wire.
Now, according to the question,
πR2 ×(18×100) = π(1/2)2 ×8
⇒ R2 ×(18×100) = (1/2)2 ×8
⇒ R2 ×(18×100) = 8/4
⇒ R2 ×(18×100) = 2
⇒R2 = 2/(18×100)
⇒ R2 = 1/(9×100)
⇒ R = √{1/(9×100)}
⇒ R = 1/(3×10)
⇒ R = 1/30
Now, thickness of the wire = 2r = 2 × 1/30 = 2/30 = 1/15 = 0.067 cm
2Thank You