Two different dice r tossed together.Find …

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Posted by Pihu Saini 6 years, 11 months ago
- 2 answers
Gaurav Seth 6 years, 11 months ago
Given that two different dice are tossed.
Total number of outcomes = 62
= 36.
(1) Let A be the event of getting a doublet.
n(A) = {1,1},{2,2},{3,3},{4,4},{5,5},{6,6}
= 6.
Required probability P(A) = 6/36
= 1/6.
(ii) Let B be the event of getting a sum of 10 of the numbers of two dice.
n(B) = {6,4},{4,6},{5,5}
= 3.
Required probability P(B) = n(B)/n(S)
= 3/36
= 1/12
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Pihu Saini 6 years, 11 months ago
1Thank You