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Find the value of k if the points (8, 1), (k, -4), (2, -5) are collinear.

Posted by Ayush Meshram 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Disha Kumari 6 years, 11 months ago

Area of triangle=1÷2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)] 0=1/2[8(-4-(-5))+k(-5-1)+2(1-(-4))] 0=1/2[8(1)+k(-6)+2(5)] 0=1/2[8-6k+10] 0=1/2[-6k+18] 0=1/2×2[-k+3] 0=-k+3 -3=-k 3=k

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CBSE > Class 10 > Mathematics