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Find the ratio in which Y-axis …

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Find the ratio in which Y-axis divides the line segment joining the point A(5,-6)and B(-1,-4) also find the coordinates of the point of divison

Posted by Ishmeet Kaur 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let the point on y-axis be P(0, y) and AP: PB = K: 1
Therefore {tex}\frac { 5 - k } { k + 1 } = 0{/tex} gives k = 5
Hence required ratio is 5: 1
{tex}y = \frac { - 4 ( 5 ) - 6 } { 6 } = \frac { - 13 } { 3 }{/tex}
Hence point on y-axis is {tex}\left( 0 , \frac { - 13 } { 3 } \right){/tex}.

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CBSE > Class 10 > Mathematics

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If 1/2 is a root of equation x^2+kx- 5/4 =0 , then what is the value of k

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CBSE > Class 10 > Mathematics