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Red light however bright it is, …

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Red light however bright it is, cannot produce the emission of electron from a clean zinc surface . But even weak ultraviolet radiation can do so. Why? X-RAY of wavelength falls on photo sensitive surface. Assuming that the work function of the surface can be neglected. Prove that the de Broglie wavelength of electron emitted will be √h×wavelength/2me
  • 2 answers

Vaibhav Soni 6 years, 11 months ago

But second part of the question

Somya Duhan 6 years, 11 months ago

Electron emmision doesnot depend on intensity of light but on the frequency. As X ray have more frequency than red light so e emission takes place. I cant understand next part.
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