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If edges of cube is increase by 10 percent what percentage LSA is incereased.

Posted by Akshat Agarwal 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 11 months ago

Let ‘a’ be the edge of the cube.
Surface area of cube = 6a² sq units
Given length of edge is increased by 10%
Hence new measure of edge = a + 10% of a = (11a/10)
Surface area of cube (after increase) = 6(11a/10)²
= (121/100) x 6a² sq units
Change in surface area = [(121/100) x 6a² ] – 6a²
= (21/100) x 6a²
% increase = [(21/100) x 6a²] x 100/ [6a² ]
= 21%

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