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Find the value of k for …

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Find the value of k for which one root of the quadratic equation kx-14x+8=0 is 2

    • Posted by Sidharth .V.Nair 6 years, 11 months ago

    CBSE > Class 10 > Mathematics
    • 6 answers

    Himanshi Sharma 6 years, 11 months ago

    K=10

    1Thank You

    Yogita Ingle 6 years, 11 months ago

    kx - 14x + 8 = 0
    If x = 2
    k(2) - 14(2) + 8 = 0
    2k - 28 + 8 = 0
    2k - 20 = 0
    2k = 20
    k = 10

     

    1Thank You

    Puja Sahoo? 6 years, 11 months ago

    Sorry, it will be K=10. My previous answer was wrong.

    2Thank You

    Shriyanshi Gupta 6 years, 11 months ago

    F(x)=kx-14x+8=0 =K(2)-14(2)+8=0 =2k-28+8=0 =2k-36=0. =2k=36 =K=36÷2 K=18

    1Thank You

    D.J Alok 6 years, 11 months ago

    Let P(x)=kx-14x+8=0 =P(2)=k(2)-14(2)+8=0 =2k-28+8=0 =2k-20=0 =2k=20 =K=10

    0Thank You

    Puja Sahoo? 6 years, 11 months ago

    K=18.

    2Thank You

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