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If thita =1√7 then find cosec^2thita-sin^2thita/cosec^2thita+sec^2thita?

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If thita =1√7 then find cosec^2thita-sin^2thita/cosec^2thita+sec^2thita?

Posted by Vivek Kumar 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 7 years, 3 months ago

Take X=theta

tan X=1/√7

sec^2x=1+1/7=8/7

Cos^2x=7/8

Sin^2x=1-7/8=1/8 ,cosec^2x=8/1

So the expression is

=8/1-(1/8)/(8)+8/7

=8/1-1/64+8/7

=(3584-7+512)/64

=4089/64=63.89

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